The Henry’s Law constant for Helium (He) in seawater of T = 20.0C and S = 35 is

Question

The Henry’s Law constant for Helium (He) in seawater of T = 20.0C and S = 35 is 3.17 x 10-4 mol kg-1 atm-1. (a) Given a partial pressure He of 5.24 x 10-6 atm, what is the equilibrium (saturation) concentration of He in the seawater? 6b . If the actual concentration of He (aq) in the seawater is 1.70 x 10-9 mol kg-1, what is the percent saturation of He in the seawater? 6c. How would the solubility of He in the seawater change (increase, decrease, not change) if the temperature was decreased to 10.0C?

Explanation / Answer

Formula :

C = k Pg

Where C is the concentration of the gas

           kis the Henry's law constant

          Pg is the partial pressure of the gas over the solution

a) C = 3.17x10-4 * 5.24x10-6 = 1.66x10-9 mol/kg

b) % = 1.66x10-9 / 1.70x10-9 * 100= 97.64%

Hope this helps. I have a little doubt in part c.

c =

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