Exercise 2.126 Naturally occurring cobalt consists of only one isotope, 59 C o ,

Question

Exercise 2.126 Naturally occurring cobalt consists of only one isotope, 59Co, whose relative atomic mass is 58.9332. A synthetic radioactive isotope of cobalt, 60Co, relative atomic mass 59.9338, is used in radiation therapy for cancer. A 1.7455 g sample of cobalt has an apparent "atomic mass" of 58.9901. Part A Find the mass of 60Co in this sample. Express your answer with the appropriate units. Exercise 2.126 Naturally occurring cobalt consists of only one isotope, 59Co, whose relative atomic mass is 58.9332. A synthetic radioactive isotope of cobalt, 60Co, relative atomic mass 59.9338, is used in radiation therapy for cancer. A 1.7455 g sample of cobalt has an apparent "atomic mass" of 58.9901. Part A Find the mass of 60Co in this sample. Express your answer with the appropriate units. Exercise 2.126 Exercise 2.126 Naturally occurring cobalt consists of only one isotope, 59Co, whose relative atomic mass is 58.9332. A synthetic radioactive isotope of cobalt, 60Co, relative atomic mass 59.9338, is used in radiation therapy for cancer. A 1.7455 g sample of cobalt has an apparent "atomic mass" of 58.9901. Naturally occurring cobalt consists of only one isotope, 59Co, whose relative atomic mass is 58.9332. A synthetic radioactive isotope of cobalt, 60Co, relative atomic mass 59.9338, is used in radiation therapy for cancer. A 1.7455 g sample of cobalt has an apparent "atomic mass" of 58.9901. Naturally occurring cobalt consists of only one isotope, 59Co, whose relative atomic mass is 58.9332. A synthetic radioactive isotope of cobalt, 60Co, relative atomic mass 59.9338, is used in radiation therapy for cancer. A 1.7455 g sample of cobalt has an apparent "atomic mass" of 58.9901. Part A Find the mass of 60Co in this sample. Express your answer with the appropriate units. Part A Find the mass of 60Co in this sample. Express your answer with the appropriate units. Part A Find the mass of 60Co in this sample. Express your answer with the appropriate units.

Explanation / Answer

let x = fractional abundance of 59Co
and 1-x = fractional abundance of 60Co
-----------------------------------------
x(58.9332) + (1-x)(59.9338) = 58.9901

On solving,

x = 0.9431

1-x = 1-0.9431 = 0.0569

So, fractional abundance of 60Co = 0.0569

Hence,

mass of 60Co in the sample = (mass of sample ) ( fractional abundance of 60Co)

= (1.7455 g) ( 0.0569)

= 0.0993 g

Therefore, mass of 60Co in the given sample = 0.0993 g

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