5. Ethanol (CH&O;), a gasoline additive, is formed by the reaction of ethylene w

Question

5. Ethanol (CH&O;), a gasoline additive, is formed by the reaction of ethylene with water. This compound is mixed with gasoline to produce "gasohol", in order to reduce our reliance on fossil fuels. This reaction releases energy What type of reaction is the reaction of ethylene with water (decomposition, combination, single displacement, or double displacement)? a. b. Is the reaction endothermic or exothermic? Are the reactants, or are the products, lower in energy content? c. d. How many moles of ethanol are formed from 7.0 moles of ethylene? e. How many grams of H:0 are needed to react completely with 3.5 moles of ethylene? f. How many grams of ethanol are formed from 7.0 moles of ethylene? g If the theoretical yield of ethanol is 92.16 g in a reaction, what is the percent yield of ethanol (% Yield) if only 88.17 g of ethanol are actually formed?

Explanation / Answer

I will answer your first question. The other post it in another question thread:

The reaction is

C2H4 + H2O -----> C2H6O

This is clearly a combination reaction.

As the reaction states that release energy, the reaction is exothermic.

if the reaction is releasing energy, then the reactants are lower in energy.

As the reaction is 1:1 mole ratio then the moles of ethanol formed will be the same moles of ethylene, 7 moles.

In the same way, 1:1 mole ratio between ethylene and water, so moles of water is 3.5 moles, then the mass:
m = 3.5 * 18 = 63 g

the grams of ethanol:
m = 7 * (2*12+6+16) = 322 g

The %yield:
% = 88.17/92.16 * 100 = 95.67%

Hope this helps

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