in order to analyze a commercial hydrogen peroxide solution by the procedure des
ID: 977520 • Letter: I
Question
in order to analyze a commercial hydrogen peroxide solution by the procedure described in this experiment, you must first dilute the commercial peroxide solution with distilled water. for example, 10 ml of a commercial peroxide solution measured with a volumetric piper was diluted to 100 ml in a volumetric flask and mixed thoroughly. 25.00 ml of the diluted peroxide was titrated. Assume that the diluted peroxide solution had a density of 1.000g mL-1. Calculate the percent H2O2 in the commercial hydrogen peroxide. in order to analyze a commercial hydrogen peroxide solution by the procedure described in this experiment, you must first dilute the commercial peroxide solution with distilled water. for example, 10 ml of a commercial peroxide solution measured with a volumetric piper was diluted to 100 ml in a volumetric flask and mixed thoroughly. 25.00 ml of the diluted peroxide was titrated. Assume that the diluted peroxide solution had a density of 1.000g mL-1. Calculate the percent H2O2 in the commercial hydrogen peroxide. in order to analyze a commercial hydrogen peroxide solution by the procedure described in this experiment, you must first dilute the commercial peroxide solution with distilled water. for example, 10 ml of a commercial peroxide solution measured with a volumetric piper was diluted to 100 ml in a volumetric flask and mixed thoroughly. 25.00 ml of the diluted peroxide was titrated. Assume that the diluted peroxide solution had a density of 1.000g mL-1. Calculate the percent H2O2 in the commercial hydrogen peroxide.Explanation / Answer
let x is concentration of commecial sample
moles of H2O2 in commercial sample= x*10/1000=0.01x
from M1V1= M2V2
0.01x= 0.1*M2 ( M2 and V2 are molarity and volume of diluted hydrogen peroxide
M2= 0.1x/0.01x =0.1x
0.1x refer to 0.1x moles/ L
1 L contains 0.1x moles = 0.1*x*34 gms of hydrogen perodixde ( Molecular weight of H2O2= 34, and mass =moles* Molecular weight)
1000ml contains 3.4x
density = 3.4x/1000 g/ml = 1
x =1000/3.4 =294.1176 moles/L
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