UPPING THE POINTS BECAUSE I NEED THIS ANSWER RIGHT NOW! ALL PARTS MUST BE ANSWER
ID: 975747 • Letter: U
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UPPING THE POINTS BECAUSE I NEED THIS ANSWER RIGHT NOW! ALL PARTS MUST BE ANSWERED TO GET ALL THE POINTS, THANK YOU IN ADVANCE!!!! I APPRECIATE THE HELP!
3. The atomic masses of nitrogen-14, titanium-48, and xenon- 129 are 14.003074 amu, 47.935878 amu, and 128.904779 amu, respectively.
C.) For 48Ti, calculate the nuclear binding energy. (in J)
D.) For 129Xe, calculate the nuclear binding energy. (in J)
F.) For 48Ti, calculate the nuclear binding energy per nucleon. (in J/nucleon)
G.) For 129Xe, calculate the nuclear binding energy per nucleon. (in J/nucleon)
Explanation / Answer
C.) mass defect of titanium = 48 – 47.935878 = 0.064 amu
1 amu = 1.657 x 10-27 kg. 0.064 amu = 1.06 x 10-28 kg
Binding energy = mass defect × c2 (from E = mc2 equation)
E = (1.06 x 10-28 kg) x (3 x 108)2m2/s2 = 9.54 x 10-12 J
D.) mass defect of titanium = 129 – 128.904779= 0.095 amu
1 amu = 1.657 x 10-27 kg. 0.095 amu = 1.57 x 10-28 kg
Binding energy = mass defect × c2 (from E = mc2 equation)
E = (1.57 x 10-28 kg) x (3 x 108)2m2/s2 = 1.413x 10-11 J
F.) Number of nucleons = 48
Energy per nucleon = (9.54 x 10-12 J)/48 = 1.98 x 10-13 J
G.) Number of nucleons = 129
Energy per nucleon = (1.413 x 10-11 J)/129 = 1.09x 10-13 J
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