A student completed the kool-Aid Spectroscopy lab and obtained the following equ

Question

A student completed the kool-Aid Spectroscopy lab and obtained the following equation after plotting consentration vs. Absorbance. Y = 1.74 x + 0.0096 What is the concentration of a sample with an absorbance of 0.44? A galvanic ceil is made using Pb(s)/Pb^2+(1.0M) and AJ(s)/Al^3+(1.0M). The cell gives a positive reading when Pb is the positive electrode. What is the correct cell notation for this system? Enter Pb for lead electrode. Pb2+ for tho lead soluton. Al for the aluminum electrode and Al3+ for the aluminium solution. What is the predicted cell potential in volts for the cell in the previous problem? Give an answer to two decimal places. A Cu/Cu2+ electrolysis cell was used to determine avagadro's number. The copper cathode increased in mass by 0.042 grams after running the cell for 452 seconds at 0.43 grams. What experimental value for

Explanation / Answer

If the Pb is in the positive electrode, means that is in the cathode. solutions in the cathode means that the reaction taking place there is the reduction so, the half reactions would be (along with the standard reduction potential):

Pb2+ + 2e- -----------> Pb(s)   E°Pb = -0.13 V
Al(s) ------------> Al3+ + 3e-   E°Al = +1.68 V

E° = -0.13+1.68 = 1.55 V

The correct notation for this cell would be then:
Pb2+|Pb ||Al3+|Al

Hope this helps

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