1) Identify the effect of increasing acidity on the solubility of the following

Question

1)

Identify the effect of increasing acidity on the solubility of the following compounds.. Clasify the effect on each compound as either "increasie solubility" or "no change in solubility"

1) BaCO3

2) Sr(OH)2

3) CuS

4) NiBr2

5) Ca3(PO4)2

6) CuI

2)

Why does the addition of acid increase the solubility of calcium phosphate? Pick the correct statement from the following 8 statements;

3)

Another metal phosphate is cobalt phosphate. It will behave similar to calcium phosphate in an acid solution. What is the net ionic equation including phases for CoPO4(s) dissolving in H3O+(aq)?

Express your answer as a net ionic equation.

It increases the phosphate ion concentration, forcing the equilibrium to the right. It decreases the phosphate ion concentration, forcing the equilibrium to the right. It decreases the phosphate ion concentration, forcing the equilibrium to the left. It increases the phosphate ion concentration, forcing equilibrium to the left. It decreases the calcium ion concentration, forcing the equilibrium to the right. It increases the calcium ion concentration, forcing the equilibrium to the right. It decreases the calcium ion concentration, forcing the equilibrium to the left. It increases the calcium ion concentration, forcing equilibrium to the left.

Explanation / Answer

1) There are six strong acids, HClO4, H2SO4, HNO3, HI,HBr and HCl. They completely dissociate in water to ClO4-, HSO3-, HNO3-, Cl-, I- and Br- ions. Therefore, these six anions will not accept protons and their salts will not be more soluble in acid solution.

Hence,

1) BaCO3 ---------> Ba+2 + CO32-

CO32- will accept protons in acid solution. Hence, BaCO3 is more soluble in acid solution.

i.e. increasing acidity , increases the solubility of BaCO3.

2) Sr(OH)2 -----------> Sr2+ + 2OH-

OH- will accept protons in acid solution. Hence, Sr(OH)2 is more soluble in acid solution.

i.e. increasing acidity , increases the solubility of Sr(OH)2.

3) CuS ---------------> Cu+2 + S2-

S2- will accept protons in acid solution. Hence,CuS will be more soluble in acid.

i.e. increasing acidity , increases the solubility of CuS.

4) NiBr2 --------------.> Ni+2 + 2Br-

Br- will not accept protons in acid solution. Hence, NiBr2 will not be more soluble in acid.

i.e. no change in solubility on increasing acidity.

5) Ca3(PO4)2 --------------> 3Ca2+ + 2PO4-3

PO4-3 will accept protons in acid solution. Hence, Ca3(PO4)2 is more soluble in acid solution.

i.e. increasing acidity , increases the solubility of Ca3(PO4)2.

6) CuI ---------------> Cu+ + l-

l- will not accept protons in acid solution. Hence,Cul will not be more soluble in acid.

i.e. no change in solubility on increasing acidity.

2)

Ans = It decreases the phosphate ion concentration, forcing the equilibrium to the right.

Ca3(PO4)2 <==> 3Ca2+ + 2PO43-

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