Thanks a ton! Y\'all are awesome! able to write the acid dissociation constant (

Question

Thanks a ton! Y'all are awesome! able to write the acid dissociation constant (Ka) for an acid-base reaction Solve for the Ka ofan acid-base reaction given equilibrium concentrations o HA(aq) +H2O(l)=H30'(aq) + A-(aq) o HA(aq)+H200) Ho (aq) +A (aq) Be (0. Calculate [H+] or [H07 as required for each of the following solutions at 25 °C, and state whether the solution is neutral, acidic, or 1.0 × 10-5 M HO- o basic o o o 10.0 MH+ 1.0 × 10-7 M HO- 3. Write a simple dissociation reaion of some acids o Acctic acid (vinegar): HCCO2H is o Hydrochloric acid: HCI o Ammonium ion: NH o Anilinium ion: C,HsNH Hydrated aluminum ion:[AIH20)%7" .Define strong acids Define weak acids 0.Define strong bases Define weak bases 12. What does a strong acid yield upon dissociation? What does a strong acid yield upon dissociation? 13. What does a weak acid yield upon dissociation? 4 What does a strong base yield upon dissociation? 1 s . what does a weak base yield upon dissociation? Define amphoteric substances, and give a couple of examples. What is Kw? What is its value at 25 °C? What is Ka? · . I GWhat is pKa? 2. What is Kb? What is pH and how is it calculated? How do we relate pH and pOH? 1· .

Explanation / Answer

acid = pH < 7

base = pH > 7

neutral : pH =7

6) a) Given that [OH-] = 1.0x 10-5 M

pOH = -log [OH-] = - log [ 1.0x 10-5 ] = 5

pH = 14 -pOH = 14-5 = 9

pH = 9

Given solution is a base.

b)

Given that [OH-] = 1.0x 10-7 M

pOH = -log [OH-] = - log [ 1.0x 10-7 ] = 7

pH = 14 -pOH = 14-7 = 7

pH = 7

Given solution is a neutral.

c)

Given that [H+] = 10 M

pH = -log [H+] = - log [10 ] = -1

   pH = -1 < 7

Given solution is a acid.

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