Need help with a problem please entropy change of UNIVERSE when 1.859 moles of C

Question

Need help with a problem please

entropy change of UNIVERSE when 1.859 moles of CH4(g) react under standard conditions at 298.15 is -886.00

Is this reaction reactant or product favored under standard conditions? reactant

Convert kJ to J   206.1 x 1000 = 206,1000

S surroundings = - (206,100 / 298.15) = - 691.26

214.7 + (-691.26) = - 476.56

1.859 x (-476.56) x ( 1/1 CH4) = -885.92

Since S universe is less than zero, the reaction is reactant favored

If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored, choose 'reactant favored'.

(enthalpy, entropy, both or product favored)

Explanation / Answer

Given chemical transformation

CH4 (g) + H2O (g) ------> CO (g) + 3H2 (g)

H° = 206.1 kJ/mol = 206.1 x 1000 = 206100 J/mol

S° = 214.7 J/K and

T= 298.15 K.

Let us calculate Gibbs free energy change (G0)

Formula,

G0 = H0 -TS0

G0 = 206100 – 298.15 X 214.7

G0 = 206100 – 64012.8

G0 = +142087.2 J/mol

G0 = + 142.087 kJ/mol

Gibbs free energy change is +ve and hence reaction is favored in reverse direction i.e. Reactants favored under standard conditions.

Gibbs free energy change sign criteria can easily tell us about the direction in which given reaction is favored.

=======================XXXXXXXXXXXXXX==================================

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.