Steam tables are frequently used to obtain values of internal energy or enthalpy

Question

Steam tables are frequently used to obtain values of internal energy or enthalpy for solving problems in which there arc changes in these properties. Use values from the steam tables E5 and F.6 in the Appendix of your textbook for this problem. Assume that internal energy is not dependent on pressure, allowing values from the table at the correct temperature to be used even if the pressure is different. Enthalpy of the liquid, however, docs depend on pressure. Make an adjustment for pressure by adding Delta(PV) to the value read from the table. For Delta (PV) calculation you can use the specific volume at the saturated pressure, the pressure difference is the desired pressure - the saturation pressure. Complete the table below using values from the steam table and adjusting enthalpy values for pressure differences as needed. Liquid water flowing at 12.0 liters per minute is drawn into a pump from a reservoir at 1.00 atm pressure, 25degree C. The pump raises the pressure of the liquid to 10.0 Bar. This pressurize water enters a boiler, coming out as saturated steam at 10.0 Bar. Determine the rate of work needed for the pump and the rate of heat needed for the boiler. You should be able to use values from above.

Explanation / Answer

for the calculation of pv= (P-Psat)*V and H*=H*PV

phase temp P PSAT VOL U H Dpv H liq 0.01 0.00611 0.00611 0.001 0 0 0 0 liq 25 1.013 0.031699 0.001003 104,88 104.89 0.000984 104.890984 liq 100 1.013 1.014 1.0435 418.94 419.04 -0.001044 419.038957 vap 100 1.013 1.014 1.21 2518.1 2230.2 -0.001210 2230.198790 liq 25 10 0.031699 0.001003 104,88 104.89 0.009998 104.899998 liq 179.9 10 10.02 1.1274 762.09 763.22 -0.022548 763.197452 vap 179.9 10 11.02 0.1941 2583.7 2015 -0.197982 2014.802018

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