The quantity of antimony in a sample can be determined by an oxidation-reduction

Question

The quantity of antimony in a sample can be determined by an oxidation-reduction titration with an oxidizing agent. A 8.91-g sample of stibnite, an ore of antimony, is dissolved in hot, concentrated HCl(aq) and passed over a reducing agent so that all the antimony is in the form Sb^3+ (ag). The Sb^3+(aq). The Sb^3+ is completely oxidized by 40.5mL of a 0.125 M aqueous solution of KBrO_3 (aq). The unbalanced equation for the reaction is BrO_3^- (aq) + Sb^3+ (aq) rightarrow Br^- (aq) + Sb^5+ (aq) (unbalanced). Calculate the amount of antimony in the sample and its percentage in the ore.

Explanation / Answer

Balanced equation is 3Sb3+ + BrO3- + 6H+---------------> 3Sb5+ +3H2O + Br-

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