Help me solve this solution stoichiometry To solve stoichiometry problems, you m
ID: 972417 • Letter: H
Question
Help me solve this solution stoichiometry
To solve stoichiometry problems, you must always calculate numbers of moles. Recall that molarity, M, is equal to the concentration in moles per liter: M = mol/L. When solutions of silver nitrate and magnesium chloride are mixed, silver chloride precipitates out of solution according to the equation 2AgNO_3(aq) + MgCl_2(aq) rightarrow 2AgCl(s) + Mg(NO_3)_2(aq) What mass of silver chloride can be produced from 1.64 L of a 0.202 M solution of silver nitrate? Express your answer with the appropriate units. The reaction described in Part A required 3.54 L of magnesium chloride. What is the concentration of this magnesium chloride solution? Express your answer with the appropriate units.Explanation / Answer
No of mol of AgNO3 = 1.64*0.202 = 0.33128 mol
No of mol of AgCl formed = 0.33128 mol
maSS OF AgCl produced = (0.33128)*143.32 = 47.5 grams
part B
No of mol of MgCl2 required = (0.33128/2) (1/ 3.54) = 0.047 M
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.