volume of HCL is 50ml that was used molarity 2M NaOH 51.0ml volume that was used

Question

volume of HCL is 50ml that was used
molarity 2M

NaOH 51.0ml volume that was used
2M molarity

initial temp of acid 21 (determination 1) and 22 (determination 2)
initial temp of base 22 (determination 1) and 21 (determination 2)

Date Data Sheet 2 volume of HCI solution, mL molarity of HCl solution, M number of moles of HC volume of NaOH solution, mL molarity of NaOH solution, M number of moles of NaOH initial temperature of acid, C initial temperature of base, C average temperature of reactants, Tinitial C final temperature of mixture, Tfinal C temperature change. AT,°C Q (heat transferred), J number of moles of HCI reacting AHneutzn, kJ mol-1 mean Hneutzn, kJ mol-1

Explanation / Answer

Calculation for First set of experiment

For Determination 1

Volume of HCl = 50 ml

Molarity of HCl = 2 M

moles of HCl = 2 x 50 = 100 mmol

Volume of NaOH = 51 ml

Molarity of HCl = 2 M

moles of HCl = 2 x 51 = 102 mmol

Initial temp of acid = 21 oC

Initial temp of base = 22 oC

Average initial temp. = 21.5 oC

Final temperature = 31 oC

dT = 31 - 21.5 = 9.5 oC

Heat transferred = 101 x 4.184 x 9.5 = 4014.5 J

moles of HCl reacted = 100 mmols

dHneut = 4.0145/0.1 mol = 40.145 kJ/mol

Similarly the other calculation may be done

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