oAon) chemistry-... Google Translate le Ess Part A 40H3Nhheat is release dby b n

Question

oAon) chemistry-... Google Translate le Ess Part A 40H3Nhheat is release dby b ning 1250g of How much heat is released by burning 125.0 g of nitromethane? 4 CH3NO2(l) + 702 (g) 4C02(g) + 6H20(g) + 4 NO2 (g) 1T,--2441.6 kJ Express your answer to four significant figures and include the appropriate units. than + 4 Noto) trom 1r- 2441.6 KJ mol My Answers | q= | 100 1.1 1 Submit Give Up Incorrect; Try Again; 4 attempts remaining; no points deducted One or more of the units you en tered is not recognized. Click help to view a list of recognized units.

Explanation / Answer

1) From the balanced equation 4 moles of Nitromethane gives -----> -2441.6 KJ

moles of 125 grams of Nitromethane = 125/61 = 2.049 moles.

4 m oles gives---------> -2441.6 KJ

2.049 moles gives ----> -2441.6*2.049/4 = -1250.7 KJ.

2) moles of water = 473/18 = 26.28 moles.

1 mole of water requires -----> 40.7 KJ

26.28 moles of water requires ----> 40.7*26.28/1 = 1069.59 KJ

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