Part A Select the member of each pair which has the higher electronegativity. Pa

ID: 971488 • Letter: P

Question

Part A

Select the member of each pair which has the higher electronegativity.

Pair #1 N vs P

Pair #2 S vs Na

N, S

N, Na

P, S

P, Na

Part B

Which of the following bonds is expected to be the most polar?

F - F

F - I

F - Br

F - Cl

Cl - I

Part C

Consider the Lewis structure for N2O shown below. What are the formal charges for the atoms from left to right in the Lewis structure?

(The figure below should be showing two lone pairs of electrons on the far left N atom and two lone pairs on the oxygen atom)

.. ..

N = N = O

.. ..

+1, +1, -2

0, 0, 0

+1, -1, 0

-1, +1, 0

0, +1, -1

N, S

N, Na

P, S

P, Na

PART A N and S ( electronegativity increases from left to right in the periodic table also decreases down the group)

Hence N is more electronegative than P and S is more electronegative than Na

PART B F-I Because electronegativity difference between Fluorine and Iodine atom is maximum hence the bond between them is polarised.

PART C -1, +1, 0

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.