& Chrome File Edit View History Bookmarks People Window Help CengageBrain - My H
ID: 970014 • Letter: #
Question
& Chrome File Edit View History Bookmarks People Window Help CengageBrain - My Home OWLv2 1 Online teaching ax nline teaching a X C Splitting Of A Signal In A Pr X .Cí cvg.cengagenow.com/ilrn/takeAssignment/takeCovalentActivity.do?!...(ikas E Screen Shot 2016-04...5.23 AM MOVIES Gogle Chrome Google Chrome Chapter 13 Mastery Revlew Toplcs] 1. NMR Spectroscopy: Proton Chemic.. pts Splitting of a signal in a proton NMR spectrum tells us the number of chemically non-equivalent hydrogens in the immediate vicinity of the hydrogen giving the signal. Predict the number of lines exhibited by hydrogens at the labeled positions in a first-order NMR spectrum. (Make the approximation that all coupling constants are equal.) 2. NMR S Spin-Spin S.. 1pts 2req NMR Spectroscopy: Spin-Spin Splitting Question Screen Shot 2016-04...9.44 AM Music YouTube Question 1 The number of lines exhibited by hydrogen(s) a is The number of lines exhibited by hydrogen(s) b is The number of lines exhibited by hydrogen(s) c is 4. NMR Spectroscopy: Determinati... pts 2req ws220.dmg Screen Shot 16-04...8.45 PM 3) PHYSICS a C The number of lines exhibited by hydrogen(s) a is The number oflines exhibited by hydrogen(s) b is The number of lines exhibited by hydrogen(s) c is Screen Shot 16-04... 2.15 PM QBIT Applied Micro Submit Answer Retry Entire Group 8 more group attempts remaining Screen Shot 016-04...2.26 PM RA NDOM FILES CELL BIO TORRENTCHEM 2101L Progress: 2/4 groups Due Apr 15 at 01:00 PM Previous Next Finish Assignment Email Instructor Save and Exit TV SHOWS gopro Cengage Learning | Cengage Technical S 15Explanation / Answer
For NMR there is a n+1 rule, where n = number of hydrogens on adjacent carbon
1)
adjacent to a, b just has one hyrdrogen. so peaks=2 (doublet)
for b,hydrogens on a, c and methyl group at b will act as adjacent hydrogens.so total H=4+2+3=9
total peaks=10
for c, total hydrogens=1(on b)+ 2(on the right carbon)=3
total peaks= 4
2)
following the above scheme,
adjacent hydrogens on a=2(on b)
peaks=3
adjacent H on b=3(a)+ 2(b)= 5
peaks=6
adjacent H on c=2(b)
peaks= 3
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.