The ionization potential of an electron in an atom or molecule is the energy req
ID: 968133 • Letter: T
Question
The ionization potential of an electron in an atom or molecule is the energy required to remove the electron. Calculate the ionization potential for a Is electron in He^+. Enter the answer in eV (electronvolt), to two significant figures and do not enter the units. Note that even though the Bohr model is wrong it gives the same result as quantum mechanics for the energies of one electron atoms. So the Rydberg equation holds but R_Hc+ (rydberg constant for He^+) = 109752 cm^-1. A free electron corresponds to n = infinity and Is in He^+ is the ground state (lowest energy state, n = 1). Also, 1 eV = 8065.73 cm^-1.Explanation / Answer
we know that
1/wave length = RHe+ x Z^2 [ ( 1/n1)^2 - (1/n2)^2]
here
n1 = 1
n2 = infinity
so
atomic number (Z) for He+ = 2
so
1 / wavelenght = RHe+ x 4 [ ( 1/1)^2 - (1/infinity)^2]
1/wave length = 4 x RHe+ [ 1- 0]
1/wave length = 4 x RHe+
1/wave length = 4 x 109752 cm-1
now
given that
1 eV ----> 8065.73 cm-1
let
y eV ---> 4 x 109752 cm-1
y = 4 x 109752 / 8065.73
y = 54.43
since energy is released , it should be negative
so
the ionization potential is -54.43 eV
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