Below is an experiement. Label each step as a oxidation or reduction reaction. S

Question

Below is an experiement. Label each step as a oxidation or reduction reaction.

Step1)

Cu (s) + 4 HNO3 -> Cu^(2+) + 2 NO3^(-) + 2 NO2 + 2 H2O

Cu^(2+) + 6 H2O -> Cu(H2O)6 &^(2+)

Description: Weight .49 of Cu wire and record . Under the heat add roughly 5 ML HNO3(nitric acid). When CU is dissolved add 10 mL of DI H2O.

Step2)

Cu(H2O)6 &^(2+) + 2 NaOH -> Cu(OH)3 + 6 H2O

Description: Add 6 MNaOH drop wise while stirring. Stop when litmus paper turns blue.

Step3)

Cu(OH)3 ->(heat) CuO + H2O

Description: Add 80 90 mL DI H2O Ba gently white string for 4 min. Allow to cool and vacuum filter precipitate. Wash with 5 mL hot water 3 times. Use 250 mL vacuum flask. Discard filtrate.

Step4)

CuO + H2SO4 -> Cu(H2O)^2+

Description: Dissolve CuO with 10 mL 3 MH2SO4. If not dissolved wash with filtrate again. Wash filter paper with DI H2O and collect in filtrate.

Step5)

Cu(H2O)6 ^(2+) + Zn -> Cu + Zn ^(2+)+ + 6 H2O

Description: Add .5 g of Zn and stir occasionally. Reaction is complete when all Zn is dissolved and solution is colorless.

Explanation / Answer

Step 1 is a oxidation reaction. Cu(0) is oxidized to Cu(II) by nitric acid.

Step 2 is a oxidation reaction. Cu(II) is oxidized to Cu(III)

Step 3 is a reduction reaction. Cu(III) is reduced to Cu(II)

Step 4 is neither a oxidation nor reduction reaction.

Step 5 is a reduction reaction. Cu(II) is reduced to Cu(0) by Zn

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