How to express the van\'t Hoff factor Here are three different methods of expres

Question

How to express the van't Hoff factor Here are three different methods of expressing the van't Hoff factor: Part A At what temperature would a 1.65 solution freeze, given that the van't Hoff factor for NaCl is 1.9? for water is 1.86 . Express your answer with the appropriate units. 3.2 Units SubmitHintsMy AnswersGive UpReview Part Part B A 0.050 solution of had an observed osmotic pressure of 3.85 at 20 . Calculate the van't Hoff factor for . Express your answer numerically. = m SubmitHintsMy AnswersGive UpReview Part

Explanation / Answer

A)

Freezing point of water, Tf = 0 oC

Depression in freezing point, Tf = i Kf m

i = 1.9

Kf = 1.86 °C kg mol-1

Molality, m = 1.65 mol kg-1

Tf = (1.9) * (1.86 °C kg mol-1) (1.65 mol kg-1)

Tf = 5.83 °C

Freezing point = Tf - Tf = -5.83 °C

B)

Osmotic pressure, = i C RT

Molarity, C = 0.05 M

Osmotic pressure, = 3.85 atm

T = 20 °C = 293.15 K

3.85 atm = i * (0.05 mol/L) * (0.0821 L atm / mol-K) * 293.15 K

i = 3.2

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.