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Baking Soda is a pure bicarbonate, NaHCO 3 . It can be mixed with vinegar for ra

ID: 966649 • Letter: B

Question

Baking Soda is a pure bicarbonate, NaHCO3. It can be mixed with vinegar for rapid chemical reaction according to the following:

CH3COOH (aq) + Na+(aq) + HCO3 -(aq) ---> Na+(aq) + CH3COO-(aq) + H2O(l) + CO2(g) - sodium ion is spectator ion.

A Good substitute for baking powder can be made by adding baking soda to an acid such as potassium hydrogen tartrate (potassium bitartrate or cream of tartar). The formula for potassium hydrogen tartrateis KHC4H4O6

Question one asks to write the chemical reaction for cream of tartar and baking soda, thus far I have: KC4H5O6 + NaHCO3 ---> KNaC4H4O6 + H2CO3

2.) Devise a substitute for baking powder by calculating the mass of cream of tartar (in g) required to react with 10g baking soda. There should be enough cream of tartar added so that all of the baking soda will react to make CO2, but no more then that.

3.) You want to substitute baking soda for baking powder in a recipie but find no cream of tartar in the pantry, instead you have plenty of vinegar. If the vinegar is a 5.15% soln. of acetic acid by mass, how many grams of vinegar would be needed to react with 15g of baking soda?

I'm not sure how to set these up, the Ka for HC4H4O6 is, Ka = 1.0E-3

Explanation / Answer

(1) The correct equation would be...

KC4H5O6 + NaHCO3 -----> KNaC4H4O6 + H2O + CO2

(2)

From balanced equaation they react in 1:1 mole ratio. we are asked to calculate the mass of Cream of tartar in grams for 10 g NaHCO3.

It is a stoichiometry problem.

10 g NaHCO3 *(1mol /84 g) * (1 mol KC4H5O6/1mol NaHCO3) * (188 g KC4H5O6/1mol )

= 22.38 g KC4H5O6

(3)

CH3COOH(aq) + Na+(aq) + HCO3-(aq) -----> Na+(aq) + CH3COO-(aq) + H2O(l) + CO2(g)

15g NaHCO3 *(1 mol/84g)*(1mol CH3COOH/1mol NaHCO3) *(60g/1mol)

= 10.71 g CH3COOH(acetic acid)

from the given mass percentage, 5.15 g of acetic acid is present in 100 g of vinegar. 10.71 g of acetic acid would be present in how many grams of vinegar.

The set up for this would be like..

10.71 g acetic acid * (100 g vinegar/5.15 g acetic acid)

= 207.96g vinegar and this could be round to 208 g.

So, we need 208 g of vinegar to react with 15 g of baking soda.

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