In case the image is not clear: I only need question 2 and 3 answered. 2. Write
ID: 965639 • Letter: I
Question
In case the image is not clear: I only need question 2 and 3 answered.
2. Write balanced net ionic equations for the following reactions:
a) Dissolving of Ni(OH)2 in nitric acid.
b) Oxidation of Cr3+ to CrO4^2- by OCl^- in alkaline solution (OCl^- is converted to Cl-)
c) The reaction of Ni^2+ that separates it from Fe^3+
d) The confirmatory test for Fe^3+
3. A solution may contain any of the Group III cations. Treatment of the solution with OCl^- in alkaline medium yields a yellow solution and a colored precipitate. The acidified solution is unaffected by treatment with NH3. The colored precipitate dissolves in nitric acid; addition of excess NH3 to this acid solution produces only a blue solution. On the basis of this information, which Group III cations are present, absent, or still in doubt?
Explanation / Answer
2 a)
Ni(OH)2 (s) + 2 HNO3(aq) --> Ni(NO3)2 (aq) + 2H2O
this is a double displacement type reaction....
b) oxidation
Cr3+ --> Cr6+ + 3e
reduction
Clo- +2e --- > Cl-
multiplying 1st by 2 and second by 3 to get a total of 6 electron exchange and by balancng H and O we have
2 Cr3+ + 3ClO- + 3 H2O --> 2 Cr6+ + 3Cl- +6 OH-
3)
c) The confirming test for Fe3+
Fe3+ (aq) + 6SCN- (aq) --> [Fe(SCN)6]3- (aq)
(blood red)
3)
Group III cations, which include Cr3+, Al3+, Fe3+ and Ni2+
From the information ...following assesment is made
A solution may contain any of the Group III cations is first treated with a mixture of OH- and OCl- solutions. This causes the iron and nickel cations to precipitate out as hydroxide salts, while the chromium and aluminum cations remain in solution:
Fe3+ (aq) + 3 OH- (aq) Fe(OH)3 (s) (precipitate)
Ni2+ (aq) + 2 OH- (aq) Ni(OH)2 (s) (precipitate)
2 Cr3+ (aq) + 3 OCl- (aq) + 10 OH- (aq) 2 CrO42- (aq) + 3 Cl- (aq) + 5 H2O (l)
Al3+ (aq) + 4 OH- (aq) Al(OH)4- (aq)
since we got yellow colour precipitate...since Ni(OH)2 is green colour and Fe(OH)3 is reddish brown
since the supernatent is of yellow colour..this suggest that Cr3+ is present as CrO42- , which is of yellow colour...and also Al3+ is absent because no change takes place when acidfied solotion is treated with NH3.
the coloured ppt dissolves is HNO3 , and addition of NH3 gives a blue colour solution....this blue colour complex should be Ni(NH3)6 .
hence Ni 2+ and Cr3+ are present.
and Al3+ and Fe3+ are absent
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