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Question

University of Wisconsin W x C WWW. Sapling earning.com 78009 EE Apps UWW D2L do Printing Q Quizlet Life Timesheet Interact C Chegg Sapling Learning LaunchPad P Pandora USPS Schooldude MY Mail R Molecular Geometry General Chemistry Un Points Possible 85 d by Sapling L d McQ A. Rock Ethan G gly Grade categor An equilibrium mixture of PCI5(g), PC 3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr, and Description: 13.2 Torr, respectively. A quantity of Cl2(g) is injected into the mixture, and the total pressure jumps to 263.0 Torr (at the moment of mixing). The system then re-equilibrates. Policies: The appropriate chemical equation is 00 You can check Pcl, g ci PCI 19 90 You can view s up on any que Calculate the new partial pressures after equilibrium is reestablished. 20 00 You can keep t you get it righ Number 21 100 You lose 5% of Torr PCI 22 93 n your quest answer. Number 23 00 Torr O Help With Th 24 97 O Web Help & 25 98 Number O Technical Su Torr 26 00 PCI 27 A Previous ® Give Up & View Solution Check Answer Next Exit Hin 28 NE 7:06 PM Search the web and Windows 4/8/2016

Explanation / Answer

Answer – We are given the at equilibrium P PCl5(g) = 217 torr, P Cl2 = 13.2 torr , P PCl3(g) = 13.2 torr

Reaction - PCl3(g) + Cl2 <-----> PCl5(g)

Calculation of Kp

We know,

Kp = P PCl5(g) / P PCl3(g) * P Cl2(g)

      = 217.0 / 13.2*13.2

      = 1.25

The total pressure is 263 torr, when we added more pressure of Cl2(g)

The added pressure of Cl2 = 263 torr – 217 +13.2+13.2

                                          = 19.6 torr

P PCl5(g) = 217 torr, P Cl2 = 13.2+19.6 torr = 32.8 torr , P PCl3(g) = 13.2 torr

    PCl3(g) + Cl2 <-----> PCl5(g)

I   13.2         32.8            217

C -x         -x                +x

E 13.2-x   32.8-x        217+x

So, Kp = P PCl5(g) / P PCl3(g) * P Cl2(g)

   1.25 = 217+x / (13.2-x)*(32.8-x)

1.25 [(13.2-x)*(32.8-x)] = 217+x

1.25x2-57.5x + 541.2 = 217+x

1.25x2- 58.5x + 324.2 = 0

Using the quadratic equation

x = -b +/- b2-4a*c / 2a

a = 1.25, b = -58.5 , c = 324.2

By solving this equation-

x = 6.42

At re-equilibrium partial pressure of each -

P PCl3(g) = 13.2-x

          = 13.2-6.42

         = 6.78 torr

P Cl2(g) = 32.8-x

             = 32.8 +6.42

            = 26.4 torr

P PCl5(g) = 217+x

               = 217+6.42

               = 223.4 torr

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