For each of the following five reactions, circle the specific chemical species t

Question

For each of the following five reactions, circle the specific chemical species that is:reduced, and draw a box around the specific chemical species that is oxidized:

a) MnO2 (s) + 2 I- (aq) +4 H+ (aq) --> Mn2+ (aq) + I2 (aq) + 2 H2O (l)
b) Cd (s) + 2 NiO(OH) (s) + 2 H2O (l) --> 2 Ni(OH)2 (s) + Cd(OH)2 (s)
c) NH4+ (aq) + 2 O2 (g) --> NO3- (aq) + 2 H+ (aq) + H2O (l)
d) 2 CuFeS2 (s) + 4 O2 (g) --> Cu2S (s) + 2 FeO (s) + 3 SO2 (g)
e) 2 K2FeO4 (aq) + 3 Zn (s) --> Fe2O3 (s) + ZnO (s) + 2 K2ZnO2 (aq)

Explanation / Answer

a

MnO2 reduced

MnO2 reduced in to Mn2+ because in MnO2 Mn oxidation state is +4

b)

NiO(OH) reduced

NiO(OH) oxidation state is +3 in priduct side it is having +2 oxidation state

c

O2 is reduced

in reactent side O2 is in 0 oxidation stae in product side -2

d

CuFeS2 get reduced

e

K2FeO4 get reduced

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