Equilibrium Worksheet For the reaction 2H_2S(g) left right arrow 2H_2 (g) + S2(g

Question

Equilibrium Worksheet For the reaction 2H_2S(g) left right arrow 2H_2 (g) + S2(g), K_c = 2.2 x 10^-4 at 1400K. Calculate the equilibrium concentration of H_2S if 0.600 moles of H_2S are placed in an empty 1L container and heated to 1400K. For the reaction CO(g) + Cl_2(g) left right arrow COCl_2(g), K_p = 0.102 at 600K. Calculate the equilibrium partial pressures of the reactants and products if 0.265atm of CO and 0.265 atm of Cl_2are placed in an empty 1L container and heated to 600K. For the reaction N_2O_4(g) left right arrow 2 NO_2(g), K_c = 6.1 x 10^-3 at 25 degree C. Nitrogen dioxide is the principal component of smog. On a particularly smoggy day, the concentration of NO_2 in the air over an urban area reaches 2.2 x 10^-7M. Calculate the equilibrium concentration of N_2O_4 in the atmosphere on this day. For the reaction H_2O(g) + Cl_2O(g) left right arrow 2 HOCl(g), K_c = 0.0900 at 25 degree C. Calculate the equilibrium concentrations of the reactants and products if 0.00432 mol of H_2O and 0.00432 mol of Cl_2O are placed in an empty 1L container and heated to 25 degree C. For the reaction CO(g) + H_2O(g) left right arrow CO_2(g) + H_2(g), K_c = 4.06 at 500 degree C. Calculate the concentrations of the reactants and products if 0.100 mol of CO and 0.100 mol of H_2O are placed in a 1.00L vessel and heated to 500 degree C. For the reaction 3H_2(g) + N_2(g) left right arrow 2NH_3(g), K_p = 4.3 x 10^-4 at 648K. Calculate the equilibrium partial pressure of NH_3 if 0.900 atm of N_2 and 0.500 atm H_2 are placed in a vessel and heated to 648K.

Explanation / Answer

K = H2^2*S2/(H2S)^2

K = 2.2*10^-4

[H2S] =0.6

[H2] = 0

[S2] = 0

in equilibrium

[H2S] =0.6 - 2x

[H2] = 0 + 2x

[S2] = 0 +x

K = H2^2*S2/(H2S)^2

2.2*10^-4= (2x)^2*x/(0.6 - 2x)^2

4x^3/(0.6 - 2x)^2 =  2.2*10^-4

4x^3 = (2.2*10^-4)(0.6 - 2x)^2

4x^3 =  (2.2*10^-4)(0.6^2 - 2*0.6x + 4x^2)

4x^3 =  (2.2*10^-4)(0.36 - 1.2x + 4x^2)

4x^3 - (2.2*10^-4)(4)x^2 +1.2*(2.2*10^-4)x - (2.2*10^-4)(0.36) = 0

x = 0.02646

[H2S] =0.6 - 2x = 0.6-2*0.02646 = 0.54708 M

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