The^1H NMR spectrum below is the starting material, 2-butanol. Provide a complet
ID: 963867 • Letter: T
Question
The^1H NMR spectrum below is the starting material, 2-butanol. Provide a complete analysis of this spectrum in your report. NMR spectrum is a powerful analytical tool used in organic chemistry to help the structure of organic compounds. It can also be used to help determine the success of a chemical reaction. When a reaction is conducted, the reaction product can be analyzed by^1H NMR spectrum to determine if the reaction was successful. The^1H NMR spectrum below is a spectrum of 2-bromonutane. Provide a complete analysis of this spectrum in your report.Explanation / Answer
In NMR Spectra of 2-Butanol, the single broad peak in between 4-5ppm id for the alcoholic hydrogen
By using the formula for the peaks (n+1) we can determine the number of peaks for the other hydrogen atoms attached to the carbon atoms
CH3 - CH (OH) -CH2 - CH3
C1 C2 C3 C4
C4 shows (2+1) = 3 peaks i.e. triplet at 0-1 ppm
C2 shows 6 sharp peaks i.e sextet at 4 ppm
C3 shows peak (pentet) (4+1)
C1 at doublet (1+1)
OH shows peak for the single hydrogen atom i.e singlet
CH3 - CH (Br) -CH2 - CH3
C1 C2 C3 C4
However the only diference in the compond of 2 -butanol and 2 - bromo butanol is of the singlet peak which is observed by the hydrogen atom of an alcholic group in 2 - butanol whereas in 2 bromo butane their is no singet peak as bromine atom does not contain any hydrogen atom so do not show the peak in the NMR spectra
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