m-acetone = S. G. Times mass_water = 0.79 Times 1.043lb = 0.824lb To determine t

Question

m-acetone = S. G. Times mass_water = 0.79 Times 1.043lb = 0.824lb To determine the number of lb-moles, we need the molecular weight (also in the pocket guide. The molecular weight of acetone is 58 1 The number of lb-moles, n. is given by n(lb - moles) = m(lb)MW = 0.824/58.1 = 0.01418 The volume is the molar volume times the number of moles The volume of one lb-mole of any ideal gas is 385.4 ft^3 at standard temperature and pressure. Therefore, the volume of the vapor from one pint of liquid acetone is given by.vol = n Times v-water = 0.01418 times 3.85.4 ft^3 = 5.466 ft^3 if you have a slightly different answer using the above equation. Notice, the above used English units. You can just as well use the metric system Unfortunately, like the engineers. Industrial Hygienists doing ventilation work tend to prefer English units, as likely do most US employers. What is the evaporated volume, in ft^3, of one quart of liquid toluene (at ' STP)? You know you must add 2 gallons of acetone to your equipment every 40 hour work week. You also know there is no acetone in any of products you produce What is the generation rate of acetone, in mg/min. while you are operating this equipment? It is safe assumption that all your acetone is going into the workspace air. The mass of 2 gallons of water is 16.69lb. The mass of 2 gallons of acetone is then 0.79 Times 16.69lb, or 14.854 lb. The generation rate is the mass released divided by the time it took to release it.

Explanation / Answer

Hello. I´m not sure wich question do you want answer, and there is not consistency units in the descripcion. so im giving you the answer to 2. with proper units and convertions

one quart = 1 liter = 0.03531 ft3

Water density = 62.43 lb/ft3

0.03531 ft3 x 62.43 lb/ft3 = 15.6 lb H20

S.G toluene = 54.33

m toluene= 54.33 x 15.6 lbH20 = 847.5 lb

Vol (lb/mol)= 847.5 lb / 0.2031 lb/mol = 4172.8 mol

Vol = 4172.8 x 385.4 ft3 = 1.61E6 ft3

Regards

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