True False Consider graph A: if y = [B] and x = time, the graph could represent

Question

True False  Consider graph A: if y = [B] and x = time, the graph could represent a first order reaction.

True False  Consider graph C: if y = [B] and x = time, the graph could represent a zero order reaction.

True False  Consider graph D: if y = 1/[B] and x = time, the slope is equal to k.

True False  Consider graph D: if y = ln[B] and x = time, the graph could represent a first order reaction.

True False  Consider graph B: if y = [B] and x = time, the graph could represent a second order reaction

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True False  Consider graph C: if y = ln[B] and x = time, the graph could represent a second order reaction.

Explanation / Answer

1. False. This is because a first order reaction needs to have a straight line, Grah A almost have it but in order to be a first order reaction, Y would have to be ln[B]. A plot for a first order reaction is lnC vs t

2. A zero order reaction plot is C vs t, so yes, this is true, this could be a zero order reaction.

3. Yes, the slope could be equal to k, cause for a plot of 1/B vs t, this is a second order reaction and the equation is 1/B = 1/Bo + kt

4. False, althought we have a straight line, the plot of a first order reaction, and the slope is negative.

5. False again, a second order equation is ruled by the previous equation.

6. Again false, a second order reaction has a positive slope.

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