Part A 1. Using your data in Part A, make a graph page using a spreadsheet progr

ID: 962452 • Letter: P

Question

Part A 1. Using your data in Part A, make a graph page using a spreadsheet program of Absorbance" (y-axis) and "Concentration of Biomarker A (x-axis, moles/L). (See the graphing section in the manual and Chem 104 graphing page on the website). This graph page must include: a data table, all appropriate titles, the computer generated best fit straight line, the equation of the best fit line and the R2 value. (Attach to back of report.) 2. Biomarker A is a biomolecule that most healthy cells have in the body. Under these assay conditions the body would normally produce a concentration of 0.50x10 M to 2.01x10 11 M A concentration greater than 2.01x10 M indicates a "Risk" of disease A concentration of 4.00x10" M or higher indicates a Very High Risk of disease. Report the concentrations of Biomarker A in your Patient's Unknown Sample (the sample you tested) and indicate whether the patient's concentrations are Low, Normal, at Risk, or at Very High Risk of disease. (Ube the graph to help determine the concentration and consider the fact that we diluted the sample.) Concentration (M) (Low, Normal, At Risk, At Very Patient Sample Code # High Risk) Part B 3. Your Unknown Molecule could be any of the following 4: Boiling Point (Corrected) Molecule A Molecule B Molecule C Molecule D 65 C 72 C 83 C 95C Which Molecule was mixed with water in your unknown Molecule A has a boiling point of 74'C. Does your sample have stronger intermolecular forces or weaker?

Explanation / Answer

To calculate absorbance values from %transmittance, we must make use of the equation

A = 2 – log10(%T)

where A = Absorbance; %T – percentage transmittance

Concentration of biomarker A (mol/L)

% Transmittance

Absorbance

1/50

97.1

0.013

2/50

96.5

0.016

3/50

93.3

0.031

4/50

91.8

0.037

For the unknown sample 29, the %Transmittance is given as 95.9%. Using the same equation, we obtain absorbance A = 0.018 (ans)