A certain gas, XY(g), decomposes as represented by the equation above. A sample

Question

A certain gas, XY(g), decomposes as represented by the equation above. A sample of each of the three gases is put in a previously evacuated container. The initial partial pressures of the gases are shown in the table below. The temperature of the reaction mixture is held constant. In which direction will the reaction proceed? (A) The reaction will form more products. (B) The reaction will form more reactant. (C) The mixture is at equilibrium, so there will be no change. (D) It cannot be determined unless the volume of the container is known.

Explanation / Answer

Solution :-

2XY ---- > X2 + Y2

Using the given initial partial pressures lets calculate the Qp and then compare it with Kp

Qp = [X2][Y2]/[XY]^2

     = [0.20][2.0]/[0.010]^2

    = 4000

Qp is greater than Kp

So the reaction will shift to left side

So the answer is option B

Reaction will form more reactant

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