50 mL 0.100 M HCl is titrated with 0.200 M NaOH. Fill in the following table v_a

Question

50 mL 0.100 M HCl is titrated with 0.200 M NaOH. Fill in the following table v_a (mL) pH 0.00 20.00 25.00 30.00 50 mL 0.100 M Benzoic Acid (Ka = 6.46 Times 10^-5) is titrated with 0.200 M NaOH. Fill in the following table V_B (mL) pH 0.00 20.00 25.00 30.00 Which of the following related acids is the strongest acid? Which is the weakest? Explain. CH_3COOH ClCH_2COOH Cl_2CHCOOH Cl_3CCOOH Which of the following related acids is the strongest acid? Which is the weakest? Explain. H_2SO_2 H_2SO_3 H_2SO_4

Explanation / Answer

HCl(aq)+NaOH(aq)H2O(l)+NaCl(aq)

equivaence point :

50 * .1 = .2 * V

V = 25 mL of NaOH added

a.) 0 mL

pH = -log[H+]

We know that initially there is 0.1 M HCl and since no NaOH has been added yet, the pH is simply:

     pH = -log[0.1 M]

     pH = 1

b.) 20 mL

50.00 x10-3L x 0.1 M HCl = .005 moles

20 x 10-3L x 0.2 M NaOH = 0.004 moles

Which results in:

0.005-0.004 = .001 moles H+(aq)

The total volume of solution is 0.050L + 0.020L = 0.070L

[H+]= (.001/.070L) =0.014285

pH= 1.8452

c) 25 mL

equivalence point for a strong acid-strong base titration, the pH = 7.0

d.) 30 mL

50.00 x10-3L x 0.1 M HCl = .005 moles

30.00 x10-3L x 0.2 M NaOH = .006 moles

[OH-] = .001moles/.080mL = .0125

pOH = 1.903

pH = 14 - 1.903 = 12.09

2.

50 mL 0.1M benzoic acid titrated with .2M NaOH

a.) 0 mL

pH = -log[H+]

     pH = -log[0.1 M]

     pH = 1

b.) 20 mL

50.00 x10-3L x 0.1 M Benzoic acid = .005 moles

20 x 10-3L x 0.2 M NaOH = 0.004 moles

Which results in:

0.005-0.004 = .001 moles H+(aq)

The total volume of solution is 0.050L + 0.020L = 0.070L

pH = log [HBz]/ [Bz - ] + pK a

pH = log [ .001/.004] + 4.189

= 3.586

using this formula u can ompute for the rest.

3.Cl3CCOOH is strongest and CH3CCOOH is weakest

Cl3CCOOH has highest electron withdrawing power and hence highest acidity

4. H2SO4 is strongest as it has highest number of oxygen atoms and H2SO2 is weakest with lowest oxygen atoms. extra oxygen help in electron withdrawal from OH groups and help to disperse nad stabilize negative charge in conjugate base.

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