Part 1: a) write the ka reaction for HCNO. b) write the equilibrium constant exp
ID: 959031 • Letter: P
Question
Part 1:
a) write the ka reaction for HCNO.
b) write the equilibrium constant expression for the dissociation of HCNO.
c) Construct (don't solve) the ICE chart for the acid dissociation of 0.100 M HCNO.
d) what is the pH of a 0.100 M HCNO solution.
Part II:
a) Write the base dissociation reaction of HONH2.
b) write the equilibrium constant expression for the base dissociation of HONH2.
c) Construct (don't solve) the ICE chart for the acid dissociation of 0.250 M HONH2.
d) what is the pH of 0.250 M HONH2.
Explanation / Answer
PART1
a)
HCNO + H2O <-> H3O+ + CNO-
b)
Ka = [H3O+][CNO-]/[HCNO]
c)
ICE chart:
species: H3O+ CNO- HCNO
initially 0 0 0.1
change +x + x -x
final x x 0.1-x
d)
pH = -logH
Ka = [H3O+][CNO-]/[HCNO]
Ka = 3.5*10^-4
3.5*10^-4= x*x/(M-x)
3.5*10^-4 = x^2/(0.1-x)
x = 0.00574
pH = -loG(x) = -log(0.00574)
pH = 2.2410
NOTE:
Consider posting all other questions in another set of Q&A. We are not allowed to answer to multiple questions in a single set of Q&A
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.