I have no clue to approach this question. The Figure at the right shows the asbo

Question

I have no clue to approach this question. The Figure at the right shows the asborption spectra of two pure compounds, A and B, each at concentration.....

Mapoob sapling learning The figure at the right shows the absorption spectra of two pure compounds, A and B, each at a concentration of 1.50 x 10 M Spectra of Compounds A and B The table below shows the measured absorbance of these standards in a 1.000-cm pathlength cell at five different wavelengths, along with the absorbance of an unknown mixture0700 of the two compounds at the same wavelengths Wavelength Compound A Compound B Mixture nth 440 470 500 530 560 (nm) standard 0.430 0.642 0.609 0.392 0.231 standarod 0.213 0.367 0.444 0.457 0.334 0.269 0.436 0.482 0.433 0.301 Wavelength, nm800 Use a spreadsheet to calculate the concentration of each compound in the mixture Number

Explanation / Answer

FOR UNKNOWN CONCENTRATION OF COMPOUND A IN THE MIXTURE,

1= COMPOUND A 1=0.430 = C=1.50*10-4 , THEN

FOR MIXTURE 0.269=? (BY CROSS MULTIPLYING)

=0.0000935 OR it can be written as 0.9*10-4 OR 9.3*10-5

2=0.642=1.50*10-4

0.436 =?, 0436*1.50*10-4/0.642=1.0*10-4,

3=0.609=1.50*10-4, 0.482=?,=0.482*1.50*10-4/0.609=1.1*10-4

4=0.392=1.50*10-4,0.433=?,=0.433*1.50*10-4/0.392=1.6*10-4

5)0.231=1.50*10-4,0.301=?, 0.301*10-4/0.231=1.9*10-4,

FOR UNKNOWN CONCENTRATION OF COMPOUND B IN THE MIXTURE,

1=A=0.213=C=1.50*10-4, THEN FOR 0.269=?,

0.269*1.50*10-4/0.213=1.89*10-4,

2=0.367=1.50*10-4, 0.436=?,0.436*1.50*10-4/0.367=1.7*10-4,

3=0.444=1.50*10-4,0.482=?, =0.482*1.50*10-4/0.444=1.62*10-4

4=0.457=1.50*10-4,0.433=?,0.433*1.50*10-4/0.457=1.4*10-4

5=0.344=1.50*10-4, 0.301=?,=0.301*1.50*10-4/0.344=1.3*10-4

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