During the experiment, a student did not follow the procedure exactly as directe
ID: 955758 • Letter: D
Question
During the experiment, a student did not follow the procedure exactly as directed. How will each of these actions affect the weight of magnesium oxide (7 on the Report Sheet)? "Fumes" were allowed to escape from the crucible. (What is the composition of the fumes?) Water was not added to the crucible. The evaporation of water caused "spattering." Water was not completely removed by evaporation. The white powder often found on objects made of aluminum is aluminum oxide, Al_2O_3. Calculate the molar mass of the aluminum oxide. If you wanted to make a molar quantity of aluminum oxide in the laboratory, how many grams of aluminum would you need to begin with?Explanation / Answer
1 a) The fumes evaporated would not effect the weight of product since the magnesium oxide formed is in the form of precipitate. The fumes could be of ammonia
b) if sufficient water is not added there are chances of some part of magnesium being retained as magnesium nitride only
c) Spattering results in decreasing of total weight of magnesium oxide so yield gets effected
d)if water is not evaporated even its weight can get added up with actual mass of magnesium oxide
2) aluminium oxide is Al2O3
its molar mass is 102 to prepare a molar quantity of aluminium oxide we require 54gms of aluminium
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