Given the change in temperature during the course of a reaction what formula wou

Question

Given the change in temperature during the course of a reaction what formula would you use to calculate q_p? A 100.0 mL sample of0.300 M NaOH is mixed with a 100.0 mL sample of0.300 M HNO_3 in a coffee cup calorimeter If both solutions were initially at 35.00^degree C and the temperature of the resulting solution was recorded as 37 00 ^degree C. determine the Delta H ^degree_ rxn (in units of kJ/mol NaOH) for the neutralization reaction between aqueous NaOH and HC1. Assume that no heat is lost to the calorimeter or the surroundings, and that the density and the heat capacity of the resulting solution are the same as water.

Explanation / Answer

First of all, I think what it is asking is the heat of neutralization between HNO3 and NaOH.

To get it, we use:

Q = mCpdeltaT

We can assume we have 200 grams of solutions taking density of water.

Q = 200g * (4.18 J/gºC) * (37 - 35) = 1672 J

Now, to express it in kJ/mol of NaOH

Moles of NaOH = 0.1 L * 0.3 mol/L = 0.03 moles

We have then:

1.672 kJ / 0.03 mol NaOH = 55.73 kJ / mol NaOH

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