Suppose a buffer solution is made from formic and (HCHO 2 ) and sodium formate (

Question

1. Suppose a buffer solution is made from formic and (HCHO2) and sodium formate (NaCHO2). What is the net ionic equation for the reaction that occurs when a small amount of hydrochloric acid is added to the buffer? A. H3O+(aq) + HCHO2(aq) H2O(l) + H2CHO2+(aq) B. HCl(aq) + HCHO2(aq) H2CHO2+(aq) + Cl–(aq)
   C. H3O+(aq) + CHO2–(aq) HCHO2(aq) + H2O(l) D. HCl(aq)+ OH–(aq) H2O(l) + Cl–(aq)
   E. H3O+(aq) + OH–(aq) 2H2O(l)
   

1. Suppose a buffer solution is made from formic and (HCHO2) and sodium formate (NaCHO2). What is the net ionic equation for the reaction that occurs when a small amount of hydrochloric acid is added to the buffer? A. H3O+(aq) + HCHO2(aq) H2O(l) + H2CHO2+(aq) B. HCl(aq) + HCHO2(aq) H2CHO2+(aq) + Cl–(aq)
   C. H3O+(aq) + CHO2–(aq) HCHO2(aq) + H2O(l) D. HCl(aq)+ OH–(aq) H2O(l) + Cl–(aq)
   E. H3O+(aq) + OH–(aq) 2H2O(l)
   

Suppose a buffer solution is made from formic and (HCHO2) and sodium formate (NaCHO2). What is the net ionic equation for the reaction that occurs when a small amount of hydrochloric acid is added to the buffer? A. H3O+(aq) + HCHO2(aq) H2O(l) + H2CHO2+(aq) B. HCl(aq) + HCHO2(aq) H2CHO2+(aq) + Cl–(aq)
C. H3O+(aq) + CHO2–(aq) HCHO2(aq) + H2O(l) D. HCl(aq)+ OH–(aq) H2O(l) + Cl–(aq)
E. H3O+(aq) + OH–(aq) 2H2O(l)
Suppose a buffer solution is made from formic and (HCHO2) and sodium formate (NaCHO2). What is the net ionic equation for the reaction that occurs when a small amount of hydrochloric acid is added to the buffer? H3O+(aq) + HCHO2(aq) H2O(l) + H2CHO2+(aq) HCl(aq) + HCHO2(aq) H2CHO2+(aq) + Cl–(aq)
H3O+(aq) + CHO2–(aq) HCHO2(aq) + H2O(l) HCl(aq)+ OH–(aq) H2O(l) + Cl–(aq)
H3O+(aq) + OH–(aq) 2H2O(l)
A. H3O+(aq) + HCHO2(aq) H2O(l) + H2CHO2+(aq) B. HCl(aq) + HCHO2(aq) H2CHO2+(aq) + Cl–(aq)
C. H3O+(aq) + CHO2–(aq) HCHO2(aq) + H2O(l) D. HCl(aq)+ OH–(aq) H2O(l) + Cl–(aq)
E. H3O+(aq) + OH–(aq) 2H2O(l)

Explanation / Answer

we know that

formic acid is the acid

and

sodium formate is the conjugate base

now

HCl is added

we know that

HCl is a strong acid

So it reacts with the base sodium formate

so

HCl + H20 --> H30+ + Cl-

now

H30+ reacts with sodium formate

H30+ (aq) + HCOO- ---> HCOOH + H20 (l)

so

the answer is option C)

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.