A common lab experiment is known as an acid-base neutralization. Typically, one

Question

A common lab experiment is known as an acid-base neutralization. Typically, one may perform the following experiment: 50.0 mL of 0.500 M HBr at 25.0°C is added to 50.0 mL of 0.500 M KOH at 25.0°C in a coffee cup calorimeter; and observe the temperature of the mixture rises to 28.2°C. What is the heat of reaction per mole of acid? Assume the mixture has a specific heat capacity of 4.18 J/(g•K) and the densities of the reactant solutions are both 1.00 g/mL.

(a) 670 J/mol

(b) 300 J/mol

(c) 27.8 kJ/mol

(d) 53.5 kJ/mol

(e) > 100 kJ/mol

Answer is (d) 53.5 kJ/mol

Explanation / Answer

100 x (28.2 -25) x 4.184 = q

q= 1338.88 J

For 1 mole compound = 1338.88 /0.025 = 53.55 kJ

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