At 80 degreeC, K_c = 1.87 times 10^-3 for the reaction PH_3BCl_3(s) PH_3(g) + BC

Question

At 80 degreeC, K_c = 1.87 times 10^-3 for the reaction PH_3BCl_3(s) PH_3(g) + BCl_3(g) Calculate the equilibrium concentration of PH_3 if a solid sample of PH_3BCI_3 is placed in a closed vessel at 80 degreeC and decomposes until equilibrium is reached. Express your answer with the appropriate units. Calculate the equilibrium concentration of BCl_3 if a solid sample of PH_3BCI_3 is placed in a closed vessel at 80 degreeC and decomposes until equilibrium is reached. Express your answer with the appropriate units. If the flask has a volume of 0.21 L. what is the minimum mass of PH_3BCl_3(s) that must be added to the flask to achieve equilibrium? Express your answer with the appropriate units.

Explanation / Answer

clearly, the ratios are 1:1:1

so

4.32*10^-2 M of each

mol = MV = (4.32*10^-2)*0.21 = 0.009072 mol ofPH3BCl3

MW PH3BCl3 =  151.1676

mass = mol*MW = 0.009072 *151.1676 = 1.3713 g

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.