At a given temperature, the elementary reaction with a rate constant of 4.30 × 1

Question

At a given temperature, the elementary reaction

with a rate constant of 4.30 × 10-2 s–1. The reverse reaction is first order in B and the rate constant is 5.80 × 10-2 s–1.

What is the value of the equilibrium constant for the reaction?
What is the value of the equilbrium constant for the reaction?

At a given temperature, the elementary reaction with a rate constant of 4.30 times 10-2 s-1. The reverse reaction is first order in B and the rate constant is 5.80 times 10-2 s-1. What is the value of the equilibrium constant for the reaction? What is the value of the equilibrium constant for the reaction?

Explanation / Answer

for A <----> B

Kf = 4.3*10^-2 s^-1

Kr = 5.8*10^-2 s^-1

K = Kf/Kr

= 4.3 * 10^-2 / (5.8*10^-2)

K = 0.741 ................... answer

when we reverse the equilibrium reaction K gets inversed

so for reaction B <---------> A

equilibrium constnat, K' = 1 / 0.741 = 1.348 .............. answer

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