3/21/2016 06:00 PM A 28.5/32 3/15/2016 12:31 PM \"th Print Calculator led Period

Question

3/21/2016 06:00 PM A 28.5/32 3/15/2016 12:31 PM "th Print Calculator led Periodic Table Gradebook Question 28 of 32 Map dbu If you were going to graphically determine the activation energy of this reaction, what points would you plot? Consider this reaction data: A products T (K) k (s) Number Number 110 To avoid rounding errors, use at least three significant figures in all values. point 1: 2750.386 275 0.386 825 0.705 Number Number point 2: E Determine the rise, run, and slope of the line formed by these points. rise run slope Number Number Number What is the activation energy of this reaction? Number J/ mol O Previous Give Up & View Solution Check AnswerNext Exit Hint

Explanation / Answer

point 1 = 1/T1 = 1/275 = 0.00363636363 and ln(0.386) = -0.95191

point 2 = 1/T2 = 1/(825) =0.001212 and ln(0.705) =  -0.349

rise = dy = -0.349- -0.95191 = 0.60291

run = dx =0.001212 - 0.00363636363 = -0.002424

slope = 0.60291/(-0.002424) = -248.72

E/R = slope

E/R = 248.72

E= 248.72*8.314 = 2067.85808 J/mol

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