van der Waals Equation The Ideal Gas Law describes the temperature, pres- sure,
ID: 952529 • Letter: V
Question
van der Waals Equation The Ideal Gas Law describes the temperature, pres- sure, and volume of an ideal gas. It is PV = nRT (4.4) where P is the pressure of the gas in kilopascals (kPa), V is the volume of the gas in liters (L), n is the number of molecules of the gas in units of moles (mol), R is the universal gas constant (8.314 L kPa/mol.K), and Tis the abso- lute temperature in kelvins (K). (Note: 1 mol = 6.02 × 1023 molecules.) Real gasses are not ideal because the molecules of the gas are not perfectly elastic-they tend to cling together a bit. The relationship between the temper- ature, pressure, and volume of a real gas can be represented by a modification of the ideal gas law called van der Waals Equation. It is 2 na P +-)(V-nb) = nRT (4.5) where P is the pressure of the gas in kilopascals (kPa), V is the volume of the gas in liters (L), a is a measure of attraction between the particles, n is the number of molecules of the gas in units of moles (mol), and b is the volume of one mole of the particles, R is the universal gas constant (8.314 L kPa/mol K), and T is the absolute temperature in kelvins (K). This equation can be solved for P to give pressure as a function of tem- perature and volume. nRT n'a V- nb V P=_nRT (4.6)
Explanation / Answer
a) PV = n RT
P = nRT / V
= 1 X 8.314 X 273 / 30 =75.657 KPa.
b)P = (nRT / v - nb) - (n2a / V2)
=(1 x 8.314 x 273 / 30 - 0.0427 ) - ( 0.396 / 302 ) =75.765 - 0.00044 =75.76456 KPa
c)POINT Of ideal gass equation 10,226.9722
20,113.4986
30,75.6574
40,56.7443
50,45.39544
60,37.8295
point of ven der waal equation
10,227.9465
20,113.7304
30,75.7645
40,56.8046
50,45.4334
60,37.8563
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