WWN116WVU: Hydrolysis c x Bbcourse Home 20160 x C Search Q&A; I Chegg.com x C sm

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WWN116WVU: Hydrolysis c x Bbcourse Home 20160 x C Search Q&A; I Chegg.com x C smartwork.wwnorton.com 551647&isStudent; 1 VU HYDROLYSIS OF SALTS Print Calculator Periodic Table Ebook Question 8 of 12 (1 point) Calculate the pHvalue of a 0.015 M solution ofpyridine, c5H5N. The Kb of pyridine is 17 x109. Enter your values for a, b, and c for the quadratic equation along with the final answer in the respective answer boxes Number a F Number Number pH Number Check Answer Q View Solution Hint i

Explanation / Answer

Kb = [HB+][OH-]/[B]

1.7*!0^-9 = (x*x)/(0.015-x)

for quadratic equation

x^2 + (1.7*10^-9)x + (-0.015)((1.7*10^-9) = 0

x^2 + (1.7*10^-9)x - 2.55*10^-11= 0

a = 1

b = 1.7*10^-9

c = - 2.55*10^-11

x = 5.048*10^-6

pOH= -log(x) = -log( 5.048*10^-6) = 5.29688

pH = 14-5.29688 = 8.7031

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