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K f is the freezing point depression constant. It depends only on the SOLVENT. P

ID: 950531 • Letter: K

Question



Kf is the freezing point depression constant. It depends only on the SOLVENT.

Problem:

Match the following aqueous solutions with the appropriate letter from the column on the right.

Tf is the decrease in the freezing point = Tf(solution) - Tf(pure solvent) m is the molality of the solution = (# moles solute / kg solvent) i is the "van't Hoff" factor = (# moles of solute particles / mole of solute) For nonelectrolytes: i = 1 For strong electrolytes: i = number of (cations + anions) For weak electrolytes: 1 < i < number of (cations + anions)

Explanation / Answer

dTf = -K*m*i

since K is the same; then

m*i = determining factor

1)

i = 1 + 3; 4

mi = 0.12*4 = 0.48

2)

i = 1+2 = 3

mi = 0.15*3 = 0.45

3)

i = 2+1 = 3

mi = 0.17*3 = 0.51

4)

i = 1

mi = 0.53

then...

order from

0.53 > 0.51 >0.48 >0.45

urea > K2S > Fe(CH3COO)3 > MnBr2