We define a quantity called the turnover number to be the maximum number of subs

Question

We define a quantity called the turnover number to be the maximum number of substrate molecules that can be converted Into product molecules per unit time by an enzyme molecule. The concentration of enzyme active sites is not necessarily equal to the concentration of enzyme molecules because some enzyme molecules have more than one active site. If the enzyme molecule has one active site, the turnover number is given by. turnover number = (Rmax/[E] = k_2 (R_max is often written as V_max) If the enzyme molecule has more than one active site, then we multiply [E]_t by the number of active sites to determine its effective concentration. Determine the value of the turnover number of the enzyme carbonic anhydrase. given that R_max for carbonic anhydrase = 249 mu mol. L^-1.s^-1 and (E]_t = 2.17 nmol - L^-1. Carbonic anhydrase has a single active site.

Explanation / Answer

Rmax= 249 micro mole/L/s

(Et) = 2.17 nmol/L

turn over enzyme = Rmax/(Et)

= 249 X 10-6 / 2.17 = 114.7465 X 10-6 =0.000114 sec

carbonichydrase has single actve site

1 mol of enzyme = 1 mol of catalytic site

turnover number per catlaytic site = 0.000114 / 1 = 0.000114 sec-1

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