Gravimetric Molarity of an unknown-easy answer- I just want to make sure I\'m do
ID: 949818 • Letter: G
Question
Gravimetric Molarity of an unknown-easy answer- I just want to make sure I'm doing it correctly...and verify the first formula on the second picture is correct. Also, are these decent results?Thank you! Disregard the .4069M , I think that's wrong! DETERMINATON OF UNKNOWN KHP SOLUTION M of NaOH used 859 2.353 13 003 sample weights: 35. 887 mg%ae 1 mg 35259 mg titrant used: 21.00 mL a0 mL 2495 mL wt %KHP: 13291.13234 13083 overall "stats": mean-13203 median 13294 RSDOl5 ppt refined "stats": mean comments: (on back) medianRSD ppt density data: wt of 10.0mL of sol'ngTHgg, density data: wt of 10.0 mL of sol'n 9.1149 g, d .9774Qg d=.9774Ag/mL mL 2.35300152 2.353.,00152 N3 Volumetric Molarity of KHP sol'n 0490 Gravimetric Molarity of KHP sol'n Central value being reported for grade: M .003 of KHP sofn 4009 M 10109 M 13 a 34 wt% KHP
Explanation / Answer
The calculation you proceed are correct and the second image which shows are fine.
One suggestion abiut calculation keep the calculated values to 4 decimals it is sufficient to get good results, more digits are welcome but 4 decimal calcuation is the standard.
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