Which of the following represents the reaction of formation of hexanal? 3C_2(s.

Question

Which of the following represents the reaction of formation of hexanal? 3C_2(s. graphite) + 6H_2(g) +1/2o_2(g) right arrow C_6H_12 O(l) 6C(s. graphite) + 6H_2(g) + 1/2O_2(g) right arrow C_6 H_12 O(l) C_6(s. graphite) + H_12(g) + O(g) right arrow 2C_6 H_12 O(l) 6C(s. graphite) + 12_H(g) + 0(g) right arrow C_6 H_12 0(l) None of the above For the reaction of combustion of hexanal, how can the delta H_R be calculated? Delta H_R = delta H^hexanal_R delta H_R = delta H^co2_F + delta H^H2O_F - delta H^haxanal_F delta H_R = delta H^hexanal_F - delta H^co2_F + delta H^H2O_F More info is needed to answer None of the above

Explanation / Answer

22)

we know that

to find the heat of formation

one mole of a given compound should be formed from its individual elements in their standard state

given

C6H120

the elements are C , H , 0

the standard state of C is C (graphite)

for H it is H2 (g)

for O it is O2 (g)

So

the reaction should be

6C (s, graphite) + 6 H2 (g) + 1/2 02 (g) ---> C6H120 (l)

So

the answer is option B

23)

combustion of hexanal is given by

C6H120 + 8.5 02 ---> 6 C02 + 6 H20

we know that

dHr = dHf products - dHf reactants

also dHf for elements is zero

so

dHr = ( 6 x dHfC02) + ( 6 x dHf H20 ) - dHf hexanal

so

the answer is E) none of the above

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