. Given the Ka values (in parentheses) for the following acids: HCl (Ka is very

Question

. Given the Ka values (in parentheses) for the following acids:

HCl (Ka is very large) HNO2 (Ka = 4.0 x 10–4); HF (Ka = 7.2 x 10–4) CH3COOH (Ka = 1.8 x 10–5) HCN (Ka = 6.2 x 10–10) C6H5COOH (Ka = 6.3 x 10–5). Rank (or list) these acids in order of decreasing strength (strongest first).

A. HCl > HF > HNO2 > C6H5COOH > CH3COOH > HCN

B. HCl > HF > HNO2 > CH3COOH > C6H5COOH > HCN

C. HCN > CH3COOH > C6H5COOH > HNO2 > HF > HCl

D. HCl > HNO2 > HF > CH3COOH > C6H5COOH > HCN

E. HCN > C6H5COOH > CH3COOH > HF > HNO2 > HCl

Explanation / Answer

A. HCl > HF > HNO2 > C6H5COOH > CH3COOH > HCN

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