1.Calculate the mass of malonic acid (C 3 H 4 O 4 , MW 104.07 g/mol) required to
ID: 948666 • Letter: 1
Question
1.Calculate the mass of malonic acid (C3H4O4, MW 104.07 g/mol) required to prepare 50.00mL of a 0.15 M malonic acid solution.
2. Calculate the mass of manganese sulfate monohydrate (MnSO4*H2O, MW 169.01 g/mol) required to prepare 50.00mL of a 0.020 M manganese sulfate solution
3. Calculate the mass of potassium iodate (KIO3,MW 213.99 g/mol) required to prepare 50.00mL of a 0.20 M potassium iodate solution.
4. Calculate the volume of 1.0 M sulfuric acid (H2SO4) required to prepare 100.00mL of a 0.080 M sulfuric acid solution. Use the formula M1V1=M2V2
5. Calculate the volume of 30% (w/w) hydrogen peroxide (H2O2) required to prepare 25.00mL of 6% hydrogen peroxide. Use the formula M1V1=M2V2
Explanation / Answer
1)
0.15 M malonic acid
Molarity = (mass / MW ) x 1000 / volume
0.15 = (mass / 104.07 ) x 1000 / 50
mass = 0.78 g
2)
Molarity = (mass / MW ) x 1000 / volume
0.02 = (mass / 169.01 ) x 1000 / 50
mass = 0.169 g
3)
Molarity = (mass / MW ) x 1000 / volume
0.20 = (mass / 213.99 ) x 1000 / 50
mass = 2.14 g
4)
M1 V1 = M2 V2
1 x V1 = 0.08 x 100
V1 = 8.00 mL
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