A student prepared this solution by mixing the following solutions: 4.00 mL of 0
ID: 947892 • Letter: A
Question
A student prepared this solution by mixing the following solutions:
4.00 mL of 0.00250 M Fe(NO3)3
3.00 mL of 0.00250 M KSCN
3.00 mL of 0.050 M HNO3
From a plot of absorbance versus concentration of [Fe(SCN)]2+, the equilibrium concentration of [Fe(SCN)]2+ was determined to be 2.8 x 10-4 M. Calculate the initial concentration of Fe3+ before the system is allowed to proceed to equilibrium.
Question 4 options:
1.20 x 10^-3 M
1.00 x 10^-3
4.32 x 10^-4
0.0480 x 10^-3 M
0.0460 X 10^-3 M
1.20 x 10^-3 M
1.00 x 10^-3
4.32 x 10^-4
0.0480 x 10^-3 M
0.0460 X 10^-3 M
Explanation / Answer
Using law of equivalence;
M1V1=M2V2
0.0025 M Fe(NO3)3 * 2 mL = M2 * 10mL
M2 = (0.0025 M * 2 mL) / 10 mL
M2 = 0.0005 M Fe3+
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