COCL2 (g) to CO (g) + cl2 (g) calculate the value of Kc, given Kp = 6.5×10^11 at

Question

COCL2 (g) to CO (g) + cl2 (g) calculate the value of Kc, given Kp = 6.5×10^11 at 298K.

4.) Given the following chemical equilibrium. calculate the value ofL given that -65 x 10m at 298 kL (R-00006 Lamin! .) A 25 Lfiask is filled with 025 mrl so, 0.20 mal so. and 0.40 ml 0, and allowed to Assume the temperature of the misture is chosen so that012 Predict the efect on the of SO as equilibrium is achieved by using O. the reaction guotiet a [SOwill decresse because K h. [SOb] will decrease because c. 150will increase tecallieQ

Explanation / Answer

relation between Kc and Kp is

Kc=Kp / (RT)n

where

n = (Total moles of gas on the products side) - (Total moles of gas on the reactants side) = 2-1 = 1

T = temperature = 298K

R = gas constant = 0.0821 L-atm/mol-K

Kc =  6.5×1011 / (0.0821 x 298)1

Kc = 6.5×1011 / 24.466

Kc = 2.656 x 1010

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.