7,8,9 please show you came to the answer 7. Consider a chemical reaction involvi
ID: 947464 • Letter: 7
Question
7,8,9 please show you came to the answer
Explanation / Answer
As we know,
Rate = k [Reactant 1] a * [Reactant 2] b
Rate = k [A]a [B]b
According to the given data for the reaction,
a=1 & b=2
Rate = k [A] [B]2
For trial 1,
Rate1 = k [1.0 M] [0.20 M]2 = 0.1 Ms-1 (Equation 1)
For trial 2,
Rate2 = k [2.0 M] [0.60 M]2 = ??? (Equation 2)
According to the equation 1,
0.1 Ms-1 = k [1.0 M] [0.20 M]2 (Where k = Rate Constant)
k = 0.1 Ms-1 / (1.0 M * 0.04 M2 )
k = 2.5 M-2 s-1
From equations 1 & 2,
eq.1/eq.2
( 0.1 Ms-1 = k [1.0 M] [0.20 M]2 ) / ( Rate2 = k [2.0 M] [0.60 M]2 )
Rate2 = ( 2.0 * 0.602 * 0.1 ) / ( 1.0 * 0.22 )
Rate for trial 2 = 1.8 Ms-1
Units of the specific rate constant = M-2s-1 or mol-2 dm6 s-1
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